Hi,
4MB is the least amount of memory you can assign to a server.
Best regards
Frank Brix Pedersen
Hi
I don't see the numbers you are seeing. Are we looking at the same -- > http://www.vmware.com/pdf/vi3_35/esx_3/r35/vi3_35_25_config_max.pdf
Best regards
Lars Liljeroth
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Hi,
4MB is the least amount of memory you can assign to a server.
Best regards
Frank Brix Pedersen
Hi,
4MB is the least amount of memory you can assign to a server.
Best regards
Frank Brix Pedersen
ahh... my glasses ... Now i found it.
Yes that is the minimum you can assign. Try and put the memory slider to the minimum value on a Vm.
Best regards
Lars Liljeroth
Thank you Guys !
> 65532MB (64GB ‐ 4MB).
The line is talking about max. memory for a VM, so I read it that you cannot assign a full 64GB (=65536MB) of memory - it is 4 MB less.
I don't think this was answered.
As BUGCHK, I think the maximum is a formula: =(64GB-4MB) =65532MB and not a range.
So, the question is: why is 4MB subtracted?
I agree with you. My question was why is 4 MB substracted?
It's not a substraction but a notation reminding you that any memory size up to 65532MB that you allocate to the vm must be a multiple of 4MB!:x
.
> My question was why is 4 MB substracted?
As said, memory is allocated in multiple of 4 MegaBytes. For 65536
MegaBytes, another Bit would be required to describe that number in
binary.
65532(10) = 0FFFC(16) = 1111.1111.1111.1110(2)
65536(10) = 10000(16) = 1.0000.0000.0000.0000(2)
Now if that bit is spend, you can describe up to 131068(10) = 0x1FFFC(16) = 1.1111.1111.1111.1110(2) MegaBytes
If you want to describe 131072 MegaBytes you do need another bit - and on and on -
oops