VirtualMachineRelocateSpec + CloneVM_Task

[RobMokkink]

The script is working so far.

The next challenge is that i have 2 cluster, each in a different site. Each site is active. each cluster has the same resourcepools and the resourcepools have the same names + the -<sitecode>. So each resourcepool is unique.

The script clones a template and put's the vm in a resourcepool on a cluster. But if i don't want to put a vm in a resourcepool, i looked at the SDK concerning VirtualMachineRelocateSpec.

In the VirtualMachineRelocateSpec there is a line that when you clone a template to vm, you must specify a resourcepool, but how to do that if i want to use the cluster default resourcepool?

The code for getting the resourcepool is:

#RESOURCE POOL FROM CLUSTER

$pool = get-resourcepool $vmpool

$poolview = get-view $pool.id

$vmrSpec.pool = $poolview.moref

But how to use the default resourcepool of a cluster?

Thanks in advance.

[RobMokkink]

I was thinking.

Every host and cluster has a resource pool, i think the pool is called resources.

If i do this interactively:

get-cluster ClusterName | get-resourcepool

I see the resourcepools in the cluster, but also the default one.

But how to use it in the script?

I tried it using

get-cluster ClusterName | get-resourcepool $vmpool

$poolview = get-view $pool.id

$vmrSpec.pool = $poolview.moref

But then vmrSpec.pool is null and the script fails.

Anyone an idea?

[ykalchev]

According to VI API documentation the ClusterComputeResource object has resourcePool property that is reference to root resource pool.

So In you case you can do

$cl = Get-View (get-cluster ClusterName).Id

$vmrSpec.pool = $cl.ResourcePool

Is this is the resource pool you are looking for ?

[LucD]

Yes, that property points to the default pool called Resources.

Just one caveat, the property is a MoRef so you will have to cast it to a ResourcePool object.

Short example with the MoveIntoResourcePool method

$respool = [http://VMware.Vim.ResourcePool|http://VMware.Vim.ResourcePool](Get-View (Get-Cluster <cluster-name>).ID).ResourcePool
$vm = Get-View (Get-VM <guest-name>).ID
 
$respool.MoveIntoResourcePool($vm.MoRef)
 

Since the forum SW doesn't like square brackets I attached the code

[RobMokkink]

ykalchev luc,

Thanks for giving me some input.

@luc

I have a question about this line:

(Get-Cluster <cluster-name>).ID).ResourcePool

Doesn't this line get all the resourcepools in the cluster?

I have a long weekend i won't be able to update the script until monday.

[LucD · Accepted solution]

No, like ykalchev said, the property ResourcePool in the ClusterComputeResource object, which is an extension of the ComputeResource object, points to the "...root resource pool".

The line is in fact

(Get-View (Get-Cluster <cluster-name>).ID).ResourcePool

- we get the cluster <cluster-name> which returns a ClusterImpl object

- with Get-View we get to the ClusterComputeResource object

- and in that object we get the property ResourcePool, which is a MoRef

[RobMokkink]

oke thanks for explaining that.

[RobMokkink]

The script now completely works oke:

$cluster = Get-View (get-cluster ClusterName).Id

$vmrSpec.pool = $cl.ResourcePool

Put's the vm in the default resourcepool of the cluster.

Next thing to do is, get the default resourcepool of a standalone esx server to make the script even more flexibel.