Hi All,
I'm working on a customer project which consists in creating a new vSAN 2-Nodes cluster and I have a question with this but I don't find any answers in VMware docs (only availability notion).
Does NSX-T Manager work with 1 appliance ? if yes, what sizing do you think is a good choice ? Medium ?
My customer wants to use microsegmentation of NSX-T
Yes, it does (I would go with Medium size). More is written here https://docs.vmware.com/en/VMware-NSX-T-Data-Center/3.2/installation/GUID-10CF4689-F6CD-4007-A33E-A9... - for production deployment it is recommended to have 3, but it will run also with 1. Not sure what support will tell you though if you mark your environment as production and have only 1 NSX Manager appliance there :).
Mind the fact that if you do not have connectivity from the TNs to the Manager node your data plane works, but management and control does not - you won't be able to do any configuration changes and vMotion VMs between hosts / connect them to different logical segments etc.
Yes, it does (I would go with Medium size). More is written here https://docs.vmware.com/en/VMware-NSX-T-Data-Center/3.2/installation/GUID-10CF4689-F6CD-4007-A33E-A9... - for production deployment it is recommended to have 3, but it will run also with 1. Not sure what support will tell you though if you mark your environment as production and have only 1 NSX Manager appliance there :).
Mind the fact that if you do not have connectivity from the TNs to the Manager node your data plane works, but management and control does not - you won't be able to do any configuration changes and vMotion VMs between hosts / connect them to different logical segments etc.
Thank you for your reply.
I understand know that if a have 1 or 3 NSX Manager is officialy supported, but in case of vSAN 2-Node architecture, are we agree there is no value of having 1 or 3 NSX Manager ? I'm thinking of that because it is possible to set up vSphere HA with highest priority for 1 NSX Manager ? of course if we disregard VMware support question
Yes, that is possible and it seems as a way to go (it is in the docs - the link that I have posted):