Hi,
I cant find any supported Single-root I/O virtualization (SR-IOV) device in Compatibility list for ESXi 5.1. Any information regarding this?
Hi,
take a look at the supported nics section in
many tx
Here are the supported requiremetns for SR-IOV;
At the bottom, you will see Supported NICs;
The following NICs are supported for virtual machines configured with SR-IOV. All NICs must have drivers and firmware that support SR-IOV. Some NICs might require SR-IOV to be enabled on the firmware.
■ | Products based on the Intel 82599ES 10 Gigabit Ethernet Controller Family (Niantic) |
■ | Products based on the Intel Ethernet Controller X540 Family (Twinville) |
■ |
If you upgrade from vSphere 5.0 or earlier to vSphere 5.1 or later, SR-IOV support is not available until you update the NIC drivers for the vSphere release. NICs must have firmware and drivers that support SR-IOV enabled for SR-IOV functionality to operate.
Cheers,
Jon
Thanks. What about DirectPath I/O compatibility? I know that some devices are supported:
But what about other PCI RS-232 resp. USB cards? I cant find any support from VMware.
You know customer is looking to use RS-232 card in VM... Im looking for solution.
Maybe better will be to go with something like DIGI AnywhereUSB TS network RJ45 --> USB/RS-232 ports?
http://www.digi.com/products/model?mid=3291
What do you think?
DirectPath I/O and SR-IOV have similar functionalty;
- With DirectPath I/O you can map only one physical funtion to one virtual machine
- SR-IOV lets you share a single physical device, allowing multiple virtual machines to connect directly to the physical funtion.
But what about other PCI RS-232 resp. USB cards? I cant find any support from VMware.
Since this is PCI and not a PCIe, this rules out SR-IOV leaving your only option DirectPath I/O.
The following USB devices are supported for passthrough from an ESX/ESXi Host to a Virtual Machine;
You know customer is looking to use RS-232 card in VM... Im looking for solution.
Have you got an example of what they are trying to achieve so that I can understand this requirement better?
Cheers,
Jon
