Hello all,
Here is my situation.
I want to setup a Win Serv 03 VM as a simple Fileserver.
Below is the config I want to use for this machine.
Environment:
ESX 3.5- using SAN storage via iSCSI.
Two LUNS:
LUN 1: Total Capacity 557GB. Configured to hold 4 drives with a total storage of 480GB.
LUN 2: Total Capacity 280GB. Configured to hold 2 drives with a total 246GB.
VM is configured to use only 2GB of RAM.
VCB Setup:
We are using Symantec Backup Exec 12.5 with the VMware agent.
We are using a WinServ 03 Box as our VCB Proxy.
How much swap space on each LUN do I need in order for VCB to successfully backup this VM?
Regards,
Phil
There isn't a swap concept as far as i know, just that VCB proxy needs space (equal or greater than) the VMDK size of the VM, if it is a fullVM backup (as it does a complete vmdk copy).
Also the datastore needs sufficient space for the VCB snapshot to get created.
There isn't a swap concept as far as i know, just that VCB proxy needs space (equal or greater than) the VMDK size of the VM, if it is a fullVM backup (as it does a complete vmdk copy).
Also the datastore needs sufficient space for the VCB snapshot to get created.
Rahqa,
Thank you for your response. I already was aware of the minimum, I was kind of looking for a rule of thumb in terms of a percentage.
Regards,
Phil
Ok, sorry in that case, if you were already aware of the info i wrote, ill try and see if i find a percentage ratio somewhere and definitely post it across to you.
thanks
Rahul