Ok so I've modified my script as follows:

#!/bin/bash

echo "Getting snapshots of VM Guests"

for vm in $(/usr/bin/vmware-cmd -l)

do

#echo "$vm"

/usr/bin/vmware-cmd "$vm" hassnapshot

if ($? eq "1") then

echo "$vm" has snapshot

fi

done

When my script gets to the "if" statement I get a "command not found" message.

Ok so I've made these changes but the commands inside my if statement aren't being executed so I checked the value of the resultcode variable. The value in this variable is 0 so it looks like it's not bringing back the result from the hassnapshot value. I see the following output:

hassnapshot() = 1

hassnapshot() =

hassnapshot() =

I need to retrieve the value of hassnapshot.

Thanks.

This worked great. Thanks for the help.

#!/bin/bash

echo "Getting snapshots of VM Guests"

cat /home/myuser/VMIPList.txt |

while read vmip

do vmname=`nslookup $vmip | grep name | awk -F'= ' '\{print $2)' | awk -F. '{print $1}'`

for vm in `/usr/bin/vmware-cmd -l`

do

        if \[ "$vm" == "$vmname" ]

        then

                name=`/usr/bin/vmware-cmd "$vm" getconfig displayname -q`

                snap=`/usr/bin/vmware-cmd "$vm" hassnapshot -q`

                if \[ "$snap" == "1" ]

                then

                   echo "Removing snapshots from $name"

                   remove=`/usr/bin/vmware-cmd "$vm" removesnapshots -q`

                   if \[ "$remove" == "1" ]

                   then

                           echo "Snapshots successfully removed from $name"

                   else

                           echo "*** Unable to remove snapshots from $name ***"

                   fi

                else

                        echo "No snapshots found for $name"

                fi

        fi

done

I'm currently working on retrofiting this code into my backup script. Hope this helps.